Chef Rita is cooking for a Sunday brunch. She knows that 222222 pancakes can feed 888 people. She is wondering how many people (p)(p)left parenthesis, p, right parenthesis she can feed with 555555 pancakes. She assumes each person eats the same quantity of pancakes.
XBarryX, yes you can, everyone calls me honey in meowplayground
Answers
Answer:
hmm that's great honey so call me Barry
\large\qquad \qquad \underline{ \pmb {{ \mathbb{ \maltese \: ANSWER :-) \: \: \text3 }}}}✠ANSWER:−)3✠ANSWER:−)3
\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: SOLUTION}}}}}✠SOLUTION✠SOLUTION
Given points (1,2) , (3,4) and (h,k) are on Line L1,
\begin{gathered} \underline\mathcal{ \bigstar So, \: Slope \: \: of \: \: Line \: \: L_1 \: \: is } \\ \\ m_1= \dfrac{4-2}{-3-1} = \sf { { }{} \frac{k - 2}{h - 1} } \\ \\ \implies \bf m_1 = \bf \frac{ - 1}{2 } = \bf\frac{ h- 2}{k - 1} \\ \\ \implies2(k - 2) = - 1(h - 1) \\ \\ \implies \boxed{ \boxed{ \bf h + 2k = 5}}...(i)\end{gathered}★So,SlopeofLineL1ism1=−3−14−2=h−1k−2⟹m1=2−1=k−1h−2⟹2(k−2)=−1(h−1)⟹h+2k=5...(i)
And
\begin{gathered} \underline\mathcal{ \bigstar \: Slope \: \: of \: \: Line \: \: L_2 \: \:joining } \\ \underline\mathcal{ points \: \: (h , k) \: and \: \: (4,3) \: \: is} \\ \\ \sf m_2 = \frac{3 - k}{4 - h} \\ \\ \end{gathered}★SlopeofLineL2joiningpoints(h,k)and(4,3)ism2=4−h3−k
\huge \mathcal{As}As
\begin{gathered} \underline\mathcal{ \maltese \: Line \: \: L_1 \: \: and \: \: L_2 \: \: are \: \: } \\ \\ \underline\mathcal{ perpendicular \: \: to \: \: each \: \: other}\end{gathered}✠LineL1andL2areperpendiculartoeachother
\therefore \: m_1m_2 = - 1∴m1m2=−1
\begin{gathered}( - \dfrac{1}{2} ) ( \dfrac{3 - k}{4 - h} ) = - 1 \\ \\ \implies \boxed{\boxed{\bf2h - k = 5}} ...(ii)\end{gathered}(−21)(4−h3−k)=−1⟹2h−k=5...(ii)
Solving (i) and (ii) we get
(h,k) = (3,1)
\bf \dfrac{k}{h} = \dfrac{1}{3}hk=31
thanks for fol lowering me
sorry
I don't know the answer ಥ‿ಥ