Question

Cheko had to paint a poster.
The length of the poster was twice of the breadth.
The perimeter of the poster was 132 cm.
Find the area of the poster.

Answer 1

Given :-

• The length of the poster was twice of the breadth. The perimeter of the poster was 132 cm.

To find :-

• Area of poster.

Solution :-

• Perimeter of poster = 132 cm

As we know that

→ Perimeter of rectangle = 2(l + b)

Where " l " is length and " b " is breadth of rectangle.

Let the breadth be x then length be 2x

• According to question

→ Perimeter of poster = 132 cm

→ 2(l + b) = 132

→ 2(2x + x) = 132

→ 3x = 132/2

→ 3x = 66

→ x = 66/3

→ x = 22 cm

Hence,

• Breadth of poster = x = 22cm

• Length of poster = 2x = 44cm

Now,

• Area of poster

→ length × breadth

→ l × b

→ 44 × 22

→ 968 cm²

Therefore,

• Area of poster is 968 cm²

Answer 2

Answer:

Question-

Cheko had to paint a poster.

The length of the poster was twice of the breadth.

The perimeter of the poster was 132 cm.

Find the area of the poster.

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Given-

Breadth= x

Length= 2x

Perimeter = 132 cm.

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To find-

Dimensions of the poster.

Area of the poster.

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Solution-

Let's first find the dimensions through the given perimeter.

$\color{black}\boxed{\colorbox{saffron}{Perimeter-2(length+breadth) }}$

$132 = 2(2x + x) \\ \\ = 132 = 2 \times 3x \\ \\ = 132 = 6x \\ \\ = \frac{132}{6} = x \\ \\ = 22 = x$

So,

Breadth =22cm

Length = 22×2= 44cm

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Now, let's find the area with the given dimensions.

$\color{black}\boxed{\colorbox{saffron}{Area - length×breadth}}$

$44 \times 22 \\ \\ = {968cm}^{2}$

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Required Answer-

$\rightarrow$ Length= 44cm

$\rightarrow$ Breadth= 22cm

$\rightarrow$ Area= ${968cm}^{2}$