Question

chem class 11 plse solve this question

Answer 1

O2(g)+2C (s) =2CO(g)

1 mole of oxygen reacts with 2 miles carbon to produce 2 miles of CO.

Now 0.245g of CO=0.245÷28=0.0088

mole and this will require 0.0088÷2=0.0044.mole of oxygen.


Every mole of oxygen contains6.022×10^23 molecules of oxygen.

Hence 0.0044 mole will contain 6.022×10^23×0.0044=2.65×10^21 molecules of oxygen.


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