Question

chemical analysis shows that a compound with a molarmass of 58.12g/mol contains 82.66% by mass carbon and 17.34%by mass hydrogen. find the empirical and molecular formulae of this compound ​

Answer 1

Answer:

C2H5 is the emperical formula

C4H10 is the molecular formula

Answer 2

Answer:

suppose,

Explanation:

To find the ratio in moles you divide by the

Ar

of each element.

Using approximate values:

Ratio in grams

C:H:O⇒

40:6.7:53.3

Ratio in moles

⇒

4012:6.71:53.316⇒

3.33:6.7:3.33

Dividing through by

3.33⇒

1:2:1

So the empirical formula is:

CH2O

OR

since 82.66/12=100.00 this compound is hydrocarbon c(n)H(2n+2)

Atomic mass of carbob is defined to be 12.00 as hydroden to be 1.008

so, 82.66/12=6.8883 atomic of carbon

correspond to, 17.34/1.008=17.202 atomic of hydrocarbon

Divding, 17.202/6.8883=2.497=2.5 atom of hydrofen for every atom

n=4

NOT SURE IF RIGHT OR NOT CAUSE I AM LEARNING IT TO :) STUDY WELL ATB(^.^)