Question

Chemical equation and reaction 0 acyivity electrolysis

Answer 1

Answer:

Reduction at cathode: 2 H+(aq) + 2e− → H2(g) At the positively charged anode, an oxidation reaction occurs, generating oxygen gas and giving electrons to the anode to complete the circuit: Oxidation at anode: 2 H2O(l) → O2(g) + 4 H+(aq) + 4e. The same half reactions can also be balanced with base as listed below.