chemical equation for formation of N2O5
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If so, you could use Hess Law for this since the enthalpies of formation of the reactions is already given. They could be combined to end up with N2O5
2( 2NO + O2 -> 2NO ) DeltaH1
4NO2 + O2 -> 2N2O5 DeltaH2
2( N2 + O2 -> 2NO ) DeltaH3
Adding those formulas will result to the cancelation of NO and NO2.
This will then result to the ff. formula:
2N2 + 5O2 -> 2N2O5
DeltaHformation = 2DeltaH1 + DeltaH2 + 2DeltaH3
= 2(-114.1kJ) + (-110.2kJ) + 2(180.5kJ)
DeltaHformation= 22.6 kJ
2( 2NO + O2 -> 2NO ) DeltaH1
4NO2 + O2 -> 2N2O5 DeltaH2
2( N2 + O2 -> 2NO ) DeltaH3
Adding those formulas will result to the cancelation of NO and NO2.
This will then result to the ff. formula:
2N2 + 5O2 -> 2N2O5
DeltaHformation = 2DeltaH1 + DeltaH2 + 2DeltaH3
= 2(-114.1kJ) + (-110.2kJ) + 2(180.5kJ)
DeltaHformation= 22.6 kJ
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