↵chemical equation of Cu2+ is treated with KI.
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Cu2+ + KI_____ CuI2 +. K+
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Explanation:
I thought of this reaction:
Cu2++2KI⟶CuI2+2K+CuX2++2KI⟶CuIX2+2KX+
But since CuI2CuIX2 doesn't exist, the I−IX− ions must reduce Cu2+CuX2+ to CuICuI and simultaneously get oxidised to I2IX<
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