Question

Chemical kinetics question

Answer 1

Answer:

We know,

t

1/2

=Ka

1−n

, n is the order and K is the rate constant.

log(t

1/2

)=logK+(1−n)loga

When log(t

1/2

) is plotted against log a, the slope is (1−n). But it is equal to -1.

Hence, 1−n=−1 or n=2.

Thus, the reaction is second order and the rate law is

dt

−d[A]

=K[A]

2

.

Answer 2

c order=0,t1/2=1/2ka

Explanation:

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