CHEMICAL THERMODYNAMICS! CLASS 11 A sample of gas present in a cylinder fitted with a frictionless piston expands against a constant pressure of 1atm from a volume of 2L to 12L. During the process it absorbs 600J of heat from the surroundings. Calculate the change in internal energy of the system.
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Answered by
5
Given:
- q= 600 J
- Initial volume= 2L
- Final Volume = 12L
- Pressure = 1atm
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Solution:
Change in volume:
= Vfinal- Vinitial
=12L - 2L
= 10L
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We know,
w= -P × Change in volume
=>w = -1 ×10 L-atm
=> w = -10 L- atm
Now 1 L-atm =101.3 J
w = -10× 101.3J
=> w = -1013 J
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According to first law of thermodynamics,
Change in energy = q+ w
=> Change in energy = 600 - 1013 J
=> Change in energy =
Answered by
3
W= -P. Change in volume
=-1×10 L. Atm
=-10 L. Atm
=-10×101.3 J
=-1013 J
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