Question

Chemicals 25.09 Observations and Calculations-Weight of the empty watch glass Weight of the watch glass + Na,co, 26.325 g Weight of the Na coz dissolved 1.325 g Volume of the solution prepared = 250 mL 1.325 x 1000 Normality of the Na,c0, solution = 0.10 (N) 250 x 53 recautions taken :) Amount of chemicals was taken accurately. 1) Last drops required to complete the volume was added by pipette. Experiment No.-5 periment—To prepare 250 mL of 0.10 N oxalic acid solution. eory--Oxalic acid is primary standard. The molecular formula of oxalic acid is (COOH),.2H2O Its Molar mass = 126 g mol- It is a dibasic acid hence its equivalent weight = 126/2 = 63.​

Answer 1

Answer:

So to prepare 1000ml.of 1N NaOH weneed=40g To prepare, 500 ml.of 0.2N NaOH we need=40 x 0.2 x 500/1000=4 g.

So to prepare 500 ml.of0.2N NaOH we require 4 g.

So dissolve 4 g NaOH, in water and the make up the Solution to 500 ml with distilled water . You will get 0.2 N NaOH Solution.