Question

Chemicla formula of easterification ,dehydration saponification

Answer 1

Esterification reaction-

C2H5OH + CH3COOH --> CH3COOC2H5 + H2O

Dehydration of ethanol-

C2H5OH ( in the presence of dehydrating agent like sulphuric acid) --> C2H4 (ethene) + H2O

Saponification reaction-

CH3COOC2H5 + NaOH → CH3-COOH + CH3-CH2-OH

Answer 2

Answer:

Esterification reaction-

C2H5OH + CH3COOH --> CH3COOC2H5 + H2O

Dehydration of ethanol-

C2H5OH ( in the presence of dehydrating agent like sulphuric acid) --> C2H4 (ethene) + H2O

Saponification reaction-

CH3COOC2H5 + NaOH → CH3-COOH + CH3-CH2-OH