✪ Chemistry ✪
1 litre of
is mixed with
Naf. Predict whether precipitation will occur or not.
Answers
★Given:-
- 1 litre of 10⁻⁴m Ca(NO₃)₂ is mixed with 10^-4m NaF.
- Ksp(CaF₂) = 1.1×10⁻¹²
★To find:-
- Whether the precipitation occurs or not.
★Solution:-
We know,
For a reaction like:
➜MA(s) ⇌ M⁺(aq) + A⁻(aq)
◖Ksp = [M⁺(aq)][A⁻(aq)]
Where,
✦ Ksp is the solubility product and an equilibrium constant for a solid substance dissolving in an aqueous solution.
The ion product will be:
➜[M⁺(aq)][A⁻(aq)]
When two solutions are mixed,the precipitate is formed if the ion product is greater than the solubility product.That is,
✦Ionic product > Ksp
➜[M⁺(aq)][A⁻(aq)] > Ksp
According to the question,
For precipitation to occur, ionic product of CaF₂ should be greater than Ksp.
i.e., [Ca⁺²][F⁻]² > Ksp
Ionic product:-
➜ Ca × F²
➜ 10⁻⁴× (10⁻⁴)²
➜ 10⁻¹²
We have,
- Ksp = 1.1×10⁻¹²
- Ionic product = 10⁻¹²
And we can see,
➜1.1×10⁻¹² > 10⁻¹²
➜ Ksp > Ionic product
Hence,
The precipitation doesnt occur.
______________
Extra information:-
When two aqueous solutions are mixed,
If Ionic product < Ksp :
- The solution is unsaturated
- No precipitation
If Ionic product = Ksp:
- The solution is saturated
- Equilibrium.
If ionic product > Ksp
- The solution is supersaturated
- Ionic solid will precipitate.
______________
Given:-
1 litre of 10⁻⁴m Ca(NO₃)₂ is mixed with 10^-4m NaF.
Ksp(CaF₂) = 1.1×10⁻¹²
To find:-
Whether the precipitation occurs or not.
★Solution:-
We know,
For a reaction like:
MA(s) ⇌ M⁺(aq) + A⁻(aq)
◖Ksp = [M⁺(aq)][A⁻(aq)]
Where,
Ksp is the solubility product and an equilibrium constant for a solid substance dissolving in an
aqueous solution.
The ion product will be:
[M⁺(aq)][A⁻(aq)]
When two solutions are mixed,the precipitate is formed if the ion product is greater than the
solubility product.That is,
Ionic product > Ksp
[M⁺(aq)][A⁻(aq)] > Ksp
According to the question,
For precipitation to occur, ionic product of CaF₂
should be greater than Ksp.
i.e., [Ca⁺²][F⁻]² > Ksp
Ionic product:-
Ca × F²
10⁻⁴× (10⁻⁴)²
10⁻¹²
We have,
Ksp = 1.1×10⁻¹²
Ionic product = 10⁻¹²
And we can see,
1.1×10⁻¹² > 10⁻¹²
Ksp > Ionic product