Question

Chemistry ( 2g CO2) solve

Answer 1

Answer:

Given:

Weight of Carbon dioxide (CO)₂ = 2g

To find:  

Mass of carbon present in 2g of  CO₂ = ?

Calculation:  

First calculate the molecular mass of (CO)²

Molecular mass = 1 (Atomic mass of C) + 2 (Atomic mass of O)

Molecular mass = 1(12) + 2(16)

Molecular mass = 12 + 32

Molecular mass = 44g.  

From the molecular mass calculation it is inferred that 12 g of carbon is present in 44g of carbon.

∴ 2g of carbon dioxide contains

= 12/44  × 2

= 6/11  

= 0.52g

Conclusion:

Mass of carbon present in 2g of  is 0.52g.

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Answer 2

Answer:

Verified by Toppr

24g

2mol

2C(s)

+

32g

1mol

O

2

→

56g

2mol

2CO(g)

Let carbon be completely consumed.

24g carbon give 56 g CO.

Let O

2

is completely consumed.

∵ 32 g O

2

give 56 g CO.

∴ 96 g O

2

Will give

32

56

×96gCO=168gCO

Since, carbon gives least amount of product, te.,56 g CO or 2 mole CO, hence carbon will be the limiting reactant.

∴ Excess reactant is O

2

.

Amount of O

2

used =56−24=32g

Amount of O

2

left =96−32=64g

32g O

2

react with 24 g carbon

∴ 96 g O

2

will react with 72g carbon.

Thus, carbon should be taken 72g so that nothing is left at the end of the reaction