Chemistry, asked by gnagaraju6303, 1 day ago

Chemistry 30 questions, 2 marks eac For a reaction, the expression for rate of reaction is given by: R = k[x]2[y]. If the concentration of X and Y is increased by 3 times, then what will be the increase in the rate of reaction?​

Answers

Answered by sanghamitra343
0

Explanation:

Let , The initial rate of reaction is given by , r=k[A]

n

........(i)

n being the order of the reaction.

Given that, rate of reaction becomes three times as the concentration of A is increased by 9 times

⟹ 3r=k[9A]

n

........(ii)

Dividing equation (ii) by (i), we get

r

3r

=

k[A]

n

k[9A]

n

=

k[A]

n

9

n

k[A]

n

3=9

n

or 3

1

=3

2n

⇒ 2n=1 or n=

2

1

∴ Rate , r=k[A]

1/2

Order of reaction =

2

1

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