Chemistry 30 questions, 2 marks eac For a reaction, the expression for rate of reaction is given by: R = k[x]2[y]. If the concentration of X and Y is increased by 3 times, then what will be the increase in the rate of reaction?
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Explanation:
Let , The initial rate of reaction is given by , r=k[A]
n
........(i)
n being the order of the reaction.
Given that, rate of reaction becomes three times as the concentration of A is increased by 9 times
⟹ 3r=k[9A]
n
........(ii)
Dividing equation (ii) by (i), we get
r
3r
=
k[A]
n
k[9A]
n
=
k[A]
n
9
n
k[A]
n
3=9
n
or 3
1
=3
2n
⇒ 2n=1 or n=
2
1
∴ Rate , r=k[A]
1/2
Order of reaction =
2
1
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