Question

- CHEMISTRY BYP
47. The energy of first excited state of hydrogen is -
(3.4eV then the KE of this orbit will be ?
(i) +3.4 ev
(ii) +6.8 ev
(iii) -13.6 ev
(iv) +13.6 ev
13
CHEMISTRY
8. Which of the following has maximum energy?
(i) [11] [11 112 111
(ii) 11 1 11 11 T I
(iii) 11 11 11 1 1 1 1
(iv) 11 11 11 11 1
9. The total possible number of orbitals for principal
quantum no. n is -
(i) n (ii) n? (iii) 2n (iv) 2n?
<<<<<<<please tell me fast ​

Answer 1

Answer:

-13.6ev. ,,,,(1)total possible orbital for principal quantum no. is n