Chemistry class 11⇒States of matter (gaseous state) 12 g of a gaseous mixture of He and methane was taken in a container and to the mixture,8 g of oxygen was added at same temperature.The pressure inside the container increased to a factor of 7/6.What was the weight percentage of methane in the original mixture?
Answers
Answered by
0
Woo Molar and volume ratios will be same (i.e) 1 : 1
∴∴ Mass of 1 mole CH4 and He will be 16 and 4g respectively.
Percentage by mass of CH4=MassofCH4/Totalmass×100
=16/20×100
=80%
hope it's help you
plz mark as branliest
Similar questions