chemistry class 12th solid state
help plz
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Number of atoms in close packaging = 0.5 mol
1 has 6.022 ×1023 particles
So that
Number of close−packed particles
= 0.5 × 6.022 × 1023 = 3.011 × 1023
Number of tetrahedral voids = 2 × number of atoms in close packaging
Plug the values we get
Number of tetrahedral voids = 2 × 3.011 × 1023
= 6.022 × 1023
Number of octahedral voids = number of atoms in close packaging
So that
Number of octahedral voids = 3.011 × 1023
Total number of voids = Tetrahedral void + octahedral void
= 6.022 × 1023 + 3.011 × 1023
= 9.03 × 1023
Explanation:
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Answer:
I don't know how much is it that way you I'll sorry please
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