Question

Chemistry
i) Oxidation Reactions. Write balanced equations for the oxidation reactions of K2S2O3 and
H202 with the solutions of T, Mn²+, Cr3+, and Ag*. Balance assuming acidic conditions. Are the
results consistent with the sample you have prepared being K2S2O8?​

Answer 1

Answer:

A trial-and-error approach to balancing chemical equations involves playing with the equationadjusting the ratio of the reactants and productsuntil the following goals have been achieved.

Goals for Balancing Chemical Equations

1. The number of atoms of each element on both sides of the equation is the same and therefore mass is conserved.

2. The sum of the positive and negative charges is the same on both sides of the equation and therefore charge is conserved. (Charge is conserved because electrons are neither created nor destroyed in a chemical reaction.)

There are two situations in which relying on trial and error can get you into trouble. Sometimes the equation is too complex to be solved by trial and error within a reasonable amount of time. Consider the following reaction, for example.

3 Cu(s) + 8 HNO3(aq)  3 Cu2+(aq) + 2 NO(g) + 6 NO3-(aq) + 4 H2O(l)

Other times, more than one equation can be written that seems to be balanced. The following are just a few of the balanced equations that can be written for the reaction between the permanganate ion and hydrogen peroxide, for example.

2 MnO4-(aq) + H2O2(aq) + 6 H+(aq)  2 Mn2+(aq) + 3 O2(g) + 4 H2O(l)2 MnO4-(aq) + 3 H2O2(aq) + 6 H+(aq)  2 Mn2+(aq) + 4 O2(g) + 6 H2O(l)2 MnO4-(aq) + 5 H2O2(aq) + 6 H+(aq)  2 Mn2+(aq) + 5 O2(g) + 8 H2O(l)2 MnO4-(aq) + 7 H2O2(aq) + 6 H+(aq)  2 Mn2+(aq) + 6 O2(g) + 10 H2O(l)

Equations such as these have to be balanced by a more systematic approach than trial and error.