Question

chemistry ka h ye ques..planks theory wala jldi solve kro

Answer 1

Explanation given below

Answer 2

ANSWER...

$frequency = 800hz \\ \\ energy = {h} \times frequency \\ \\ point \: to \: be \: notice \: is \: that \: this \: is \: \\ the \: energy \: of \: 1 \: photon \: so \: energy \\ of \: n \: photon \: will \: be.... \\ \\ energy = n \times h \times frequency \\ \\ where \: h \: is \: planks \: constant \\ \\ acc \: to \: question \\ \\ power = 1 \times {10}^{3} \: watt \\ \\ power = \frac{energy}{time} \\ \\ 1 \times {10}^{3} = \frac{h \times n \times frequency}{1 \: sec} \\ \\ {10}^{3} = \frac{6.26 \times {10}^{ - 34} \times n \times 800 }{1} \\ \\ \frac{ {10}^{3} }{6.26 \times {10}^{ - 34} \times 8 \times {10}^{2} } = n \\ \\ \frac{ {10}^{35} }{6.26 \times 8} = n \\ \\ 0.0189 \times {10}^{35} = n \\ \\ n = 1.89 \times {10}^{33}$