Question

Chemistry NTSE Question A burner consumes one gram of LPG in 11 sec. What is the power of consumption of burner in KW if Cv of LPG is 55 kJ/g. (a) 5 kW (b) 10 kW (c) 5.5 kW (d) None of these

Answer 1

Cv of LPG = 55 kJ/g
When 1g is used, 55kJ is produced.
time = 11sec

power = 55/11 = 5kW

answer is A.

Answer 2

A burner consumes one gram of LPG in 11 sec. What is the power of consumption of burner in KW if Cv of LPG is 55 kJ/g. a 5 kW