Question

chemistry numericals plz answer dedo koi​

Answer 1

Answer:

0.34 gram

Explanation:

given:-

Molarity = 0.05M

volume = 40cm³ = 40/1000 litre

let the mass of silver nitrate be w,

molecular weight of silver nitrate (AgNO3) = 108+14+16×3 = 122+48 = 170 grams

Molarity = (w×1000)/(Mol. wt. × vol. of solution in litre)

=> 0.05 = (1000w)/(40×170)

=> (0.05×6800)/1000 = w

=> 0.34 = w

=> w = 0.34 gram

Answer 2

Answer:

okay ji help karunga myself nahed nice to meet you