Question

CHemistry Question:-

The pressure of a gas A(P_A)is 3atm when it occupies 5L of Volume .Calculate the final pressure when it is compressed to 3L volume at constant temperature.​

Answer 1

Answer:

Applying Boyle's law; P1V1=P2V2

5×2=1.6×P2

Therefore final pressure; P2 = 1.610=6.25atm

Answer 2

Answer:-

Initial Condition:-

• V1=5L
• P1=3atm

Final condition:-

• V2=3L
• P2=?

We know that.

• According to Boyle's law

$\boxed{\sf P_1V_1=P_2V_2}$

$\\ \sf\longmapsto 3\times 5=3P_2$

$\\ \sf\longmapsto 15=3P_2$

$\\ \sf\longmapsto P_2=\dfrac{15}{3}$

$\\ \sf\longmapsto P_2=5atm$