Chemistry Questions......//
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p atom =corner =8
contribution of each corner=1/8
p=8*1/8=1
Q=face centre =6
c4 axis passes through two opp. face centre
q=6-2=4
contribution of face centre =1/2
q=4*1/2=2
so formula =pq2
contribution of each corner=1/8
p=8*1/8=1
Q=face centre =6
c4 axis passes through two opp. face centre
q=6-2=4
contribution of face centre =1/2
q=4*1/2=2
so formula =pq2
Answered by
1
p atom =corner =8
contribution of each corner=1/8
p=8*1/8=1
Q=face centre =6
c4 axis passes through two opp. face centre
q=6-2=4
contribution of face centre =1/2
q=4*1/2=2
so formula =pq2
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