Question

Chemistry Quiz :-

An ancient coin made of pure gold weighs 11.58g. Find its volume when the density of gold is 19,300 kg/m^3.

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Answer 1

Answer:

I hope it's helpful for you

Answer 2

Given that : An ancient coin made of pure gold weighs 11.58g. Density of gold is 19,300 kg/m³.

Need To FinD : Volume of coin ?

Formula NeedeD : Volume = Weight / Density

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❍ let's first convert the density of gold into g/m³ from kg/m³ for solving this question easily !

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$\qquad\longrightarrow\sf {\green{19300kg/m^{3}\; into \:g/m^{3}}}$

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$\qquad\longrightarrow\sf {\blue{19300 {×} 0.001}}$

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$\qquad\longrightarrow\sf {\orange{ 19.3g{/}m³}}$

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$\underline{\bigstar\:\boldsymbol{According\: to\: Question \: :}}$

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$\qquad\twoheadrightarrow\sf {\pink{Volume =\: \dfrac{[Weight]}{[Density]}}}$

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$\qquad\twoheadrightarrow \sf {\purple{Volume =\: \dfrac{[11.58]}{[19.3]}\: m^{3}}}$

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$\qquad\twoheadrightarrow\boxed{\underline{\pink{\mathfrak{Volumne = 0.6cm^{3}}}}}$

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$\rule{200}2$

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$\quad\footnotesize\bf{\red{\dag}\:\underline{\pink{\frak{ Therefore \::}}}}$

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$\therefore{\red{\underline{\sf{Hence, The\; Volume\; of \;pure \;gold \;Coins\; is\; \rm{0.6 cm³}}}}}$

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$\qquad\qquad\boxed{\underline{\underline{\pink{\bigstar \:\bf\:Formula\:Used\:Here\:\bigstar}}}}$

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• $\dashrightarrow\sf {\green{Volume =\: \dfrac{[Weight]}{[Density]}}}$

• $\dashrightarrow\sf {\blue{V = \: Volume}}$

• $\dashrightarrow\sf {\green{W = \; Weight}}$

• $\dashrightarrow\sf {\blue{D = \; Density }}$

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$\rule{200}2$