Question

Chemistry: What volume of 0.10 M H2S04 must be added to 50 mL of a 0.10 M NaOH Solution to make a solution in which the molarity of the H2SO4 is 0.050 M?

Answer 1

Answer: 100 ml

Explanation:

The expression used will be :

$n_1M_1V_1-n_2M_2V_2=n_3M_3V_3$

where,

$n_1$ = basicity of $H_2SO_4$ = 2

$n_2$ = acidity of $NaOH$ = 1

$M_1$ = concentration of $H_2SO_4$ = 0.10 M

$M_2$ = concentration of NaOH = 0.10 M

$V_1$ = volume of $H_2SO_4$ = v ml

$V_2$ = volume of NaOH = 50 ml

$n_3$ = basicity of resulting $H_2SO_4$ = 2

M = concentration of left $H_2SO_4$ = 0.050 M

V = volume of $H_2SO_4$ = (v + 50) ml

Now put all the given values in the above law, we get the volume of $H_2SO_4$ added.

$(2\times 0.1M\times v)-(1\times 0.1M\times 50ml)=(2\times 0.05\times (v+50)ml)$

By solving the terms, we get :

$v=100ml$

Therefore, the volume of the $H_2SO_4$ added will be, 100 ml