Chemistry, asked by rubinakareem3200, 9 months ago

Chemistry-XI
н'][ОН ]
=1.8 x 10-16 mol dm
[HO]
H,O, i.e., [HO] in pure water may be calculated to be
1 giving 55.5 mol dm
in very large excess and very few of its molecules undergo
n remains effectively constant. Constant concentration of
nultiplied with K to get another constant called K.
01x10-4 = [HT][OH]
led K of water of 25°C
0]=[H" ][OH]
w = [H' ][OH] = 10-at 25 °C.
duct of water or dissociation constant of water. The value of
nes when temperature is increased from 0 °C to 100 °C.
is not regular. The effect of temperature on K. is shown in
Table (8.4) K at various
quantity of acid or base is
temperatures.
Temp.
nains the same, but [H] and
(°C)
nyhow, in neutral water
0.11x10-14
]=[OH]
0.30x10-14
1.0x10-14
1=10-14
3.00x10-14
] =10-14
7.5x10-14
*]=10-'mol dm
H]=10 'mol dm
ut of 55.5 moles of pure water in one dm of it, only 10 moles
ny weak electrolyte. At 40 °C,
Kw
w
0
10
25
40
100
-3

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Answered by supriyapujahari4

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