Question

ches.
2.
A 8000kg engine pulls a train of 5 wagons, each of 2000kg, along a horizontal track. If the
engine exerts a force of 40000N and track offers a friction of 5000N, then calculate:.
(c) the force of wagon 1 on wagon 2.​

Answer 1

$\huge\underline\bold\blue{ƛƝƧƜЄƦ}$____________________________________

$\blue\star$Mass of engine = 8000

$\blue\star$Mass of each wagon = 2000kg

$\blue\star$No of wagon = 5

$\blue\star$Total mass of train = 8000+2000×5

=18000kg

______________________________________

$\blue\star$Force = 40,000N

$\blue\star$Total resistance = 5000N

$\blue\star$Total accelerating force = F - R

=40,000 - 5000

= 35000

Let the acceleration be a

______________________________________

$</strong><strong>\blue\star$Acceleration = $\dfrac{Acceleration force}{mass}$

a = $\dfrac{35000}{18000}$ =1.94m\s²

______________________________________

Frictional resistance of 4 wagons = 5000 × 2000 × 4 × 1.94 = 15552N

Hence total force exerted by wagon one on wagon 2 = Acceleration force + Frictional resistance

= 2222.22 + 15552

= 17774.22N

Hope it helps

Answer 2

Explanation:

\huge\underline\bold\blue{ƛƝƧƜЄƦ}

ƛƝƧƜЄƦ

____________________________________

\blue\star⋆ Mass of engine = 8000

\blue\star⋆ Mass of each wagon = 2000kg

\blue\star⋆ No of wagon = 5

\blue\star⋆ Total mass of train = 8000+2000×5

=18000kg

______________________________________

\blue\star⋆ Force = 40,000N

\blue\star⋆ Total resistance = 5000N

\blue\star⋆ Total accelerating force = F - R

=40,000 - 5000

= 35000

Let the acceleration be a

______________________________________

< /strong > < strong > \blue\star</strong><strong>⋆ Acceleration = \dfrac{Acceleration force}{mass}

mass

Accelerationforce

a = \dfrac{35000}{18000}

18000

35000

=1.94m\s²

______________________________________

Frictional resistance of 4 wagons = 5000 × 2000 × 4 × 1.94 = 15552N

Hence total force exerted by wagon one on wagon 2 = Acceleration force + Frictional resistance

= 2222.22 + 15552

= 17774.22N

Hope it helps