Chetan buys two kinds of cloth materials for school uniforms. Shirt material that costs him Rs. 50 per meter and trouser material that costs him Rs. 100 per meter each. For every 4 meters of shirt material, he buys 3 meters of trouser material. He sells the materials at 12% and 10% profit respectively. His total sale is Rs.55400. How much trouser material did he buy?
Answers
Answer:
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Step-by-step explanation:
So he bought 1.5 x meters of shirt material and sold it at RS 56 per meter. So his total sales of shirt material is 1.5 x * 56 = 84 x. And he bought x meters of trouser material and sold it at RS 99 per meter. So his total sales of trouser material is x * 99 = 99x.
Answer:
Equations with linear expressions in one variable only are known as linear equations in one variable.
An algebraic equation is an equality involving variables. It has an equality sign(=). The expression on the left of the equality sign is the Left Hand Side (LHS). The expression on the right of the equality sign is the Right Hand Side (RHS).
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Solution:
Let Chetan bought 2x m of trouser material and 3x m of the shirt material.
Per metre selling price(S.P) of the trouser material = ₹90+90×12/100
= 90 + 1.2× 9
= 90 + 10.8
=₹100.80
Per metre selling price(S.P) of trouser of shirt material
= ₹50+ 50× 10/100
= ₹ 50 + 5
=₹55
Given: total amount of sale= ₹ 36660
100.80 x (2x) + 55 x (3x) = ₹36660
201.60 x + 165x = 36660
366.60 x = 36660
X= 36660/366.60
x = 100
Trouser material = 2x m = (2×100)m = 200m.
Hasan bought 200 m of trouser material.
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