child drops a ball from a height of 10m assume that it is velocity increases uniformly at the rate of 10 M per square find the velocity with which the ball strikes the ground 2) time taken by ball to reach the ground.
Answers
Answered by
8
use equation of motion
v.v = u.u + 2.a.s
where v is final velocity and u is initial velocity and s is displacement that is height.
for time use
v = u + a.t
where t is time taken.
v.v = u.u + 2.a.s
where v is final velocity and u is initial velocity and s is displacement that is height.
for time use
v = u + a.t
where t is time taken.
Attachments:
Answered by
16
ANSWER
Acceleration(a) = 10 m/s²
Initial Velocity(u) = 0 m/s
Final velocity be 'v' m/s
g = 10 m/s²
Now Using equation of motion:
v² + u² = 2gh
v = √2gh
= √200
= 10√2 m s⁻¹
Now, Let the time be 't' sec.
Equation of motion:
h = ut + 1/2gt²
h = 1/2gt²
t = √(2h/g)
t = √2 sec
∴ Velocity = 10√2 m s⁻¹
∴ Time = √2 second
Similar questions