Question

child has 6 trousers and 12 shirts. How many different outfits can he wear? *

Answer 1

He can wear up to 18 different outfits.

but it depends to the child as he can cut outfits and make the new one.

PLEASE MARK ME AS BRAINLIEST ; )

Answer 2

How many different outfits can the child wear?

Given :-

No. of Trousers = 6

No. of Shirts = 12

To Find :-

How many different outfits can the child wear?

Solution :-

In order to find out the number of possible combinations of shirts and trousers the child can wear, we need to multiply the no. of trousers with the no. of shirts.

No. of possible combinations = 12*6 = 72 outfits.

In order to confirm the total possible outfits, let us have a look over the combinations.

Let T denote Trousers and S denote Shirts.

$S_{1}T_{1},\: S_{1}T_{2},\: S_{1}T_{3},\: S_{1}T_{4},\: S_{1}T_{5},\: S_{1}T_{6},\:\\S_{2}T_{1},\: S_{2}T_{2},\: S_{2}T_{3},\: S_{2}T_{4},\: S_{2}T_{5},\: S_{2}T_{6},\:\\S_{3}T_{1},\: S_{3}T_{2},\: S_{3}T_{3},\: S_{3}T_{4},\: S_{3}T_{5},\: S_{3}T_{6},\:\\S_{4}T_{1},\: S_{4}T_{2},\:S_{4}T_{3},\:S_{4}T_{4},\:S_{4}T_{5},\:S_{4}T_{6},\:\\S_{5}T_{1},\: S_{5}T_{2},\:S_{5}T_{3},\:S_{5}T_{4},\:S_{5}T_{5},\:S_{5}T_{6},\:\\S_{6}T_{1},\: S_{6}T_{2},\:S_{6}T_{3},\:S_{6}T_{4},\:S_{6}T_{5},\:S_{6}T_{6},\:$

$S_{7}T_{1},\: S_{7}T_{2},\:S_{7}T_{3},\:S_{7}T_{4},\:S_{7}T_{5},\:S_{7}T_{6},\:\\S_{8}T_{1},\: S_{8}T_{2},\:S_{8}T_{3},\:S_{8}T_{4},\:S_{8}T_{5},\:S_{8}T_{6},\:\\S_{9}T_{1},\: S_{9}T_{2},\:S_{9}T_{3},\:S_{9}T_{4},\:S_{9}T_{5},\:S_{9}T_{6},\:\\S_{10}T_{1},\: S_{10}T_{2},\:S_{10}T_{3},\:S_{10}T_{4},\:S_{10}T_{5},\:S_{10}T_{6},\:\\S_{11}T_{1},\: S_{11}T_{2},\:S_{11}T_{3},\:S_{11}T_{4},\:S_{11}T_{5},\:S_{11}T_{6},\:\\S_{12}T_{1},\: S_{12}T_{2},\:S_{12}T_{3},\:S_{12}T_{4},\:S_{12}T_{5},\:S_{12}T_{6},\:$

⇒ The total number of different outfits the child can wear is 72.