Question

child walks 6 m towards west and then 20 in towards south. He then turns east and
walks another 12 m. Then he walks 12 m towards north. How far is he from his initial
osition?​

Answer 1

1. Distance walked towards west (OA) =6m
2. Distance walked towards south (AB) =20m
3. Distance walked towards East (BC) =12m
4. Distance walked towards North (CD) =12m

$5. ED = CE - CD$

$= 20 - 12$

$= 8 \: m$

$6. EO = EA - OA$

$= 12 - 6$

$= 6 \: m$

$In \: \triangle OED ,$

/* By Pythagoras Theorem */

$OD^{2} = DE^{2} + EO^{2}$

$= 8^{2} + 6^{2}$

$= 64 + 36$

$= 100 \: -- (1)$

$Now, \red{Distance \: from \: initial \: point \: to}$

$\red{terminal \: point ( OD ) }= \sqrt{100}$

$\green { = 10 \: m}$

•••♪