Chimi dissolved 20th of common salt and 50 of sugar with 250g of water. What is the sum of mole fraction of the three components present in the solution?
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Answer:Explanation:
Answer:Explanation:Mas of common salt (solute)=40 g
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 g
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 gmass of solution=320+40
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 gmass of solution=320+40 =360 g
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 gmass of solution=320+40 =360 gconcentration of solution=
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 gmass of solution=320+40 =360 gconcentration of solution= massofsolution
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 gmass of solution=320+40 =360 gconcentration of solution= massofsolutionM
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 gmass of solution=320+40 =360 gconcentration of solution= massofsolutionM mass
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 gmass of solution=320+40 =360 gconcentration of solution= massofsolutionM mass
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 gmass of solution=320+40 =360 gconcentration of solution= massofsolutionM mass ofsolute
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 gmass of solution=320+40 =360 gconcentration of solution= massofsolutionM mass ofsolute
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 gmass of solution=320+40 =360 gconcentration of solution= massofsolutionM mass ofsolute ×100
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 gmass of solution=320+40 =360 gconcentration of solution= massofsolutionM mass ofsolute ×100360
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 gmass of solution=320+40 =360 gconcentration of solution= massofsolutionM mass ofsolute ×10036040
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 gmass of solution=320+40 =360 gconcentration of solution= massofsolutionM mass ofsolute ×10036040
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 gmass of solution=320+40 =360 gconcentration of solution= massofsolutionM mass ofsolute ×10036040 ×100=11.11%
Answer:Explanation:Mas of common salt (solute)=40 gMass of water (soluted) =320 gmass of solution=320+40 =360 gconcentration of solution= massofsolutionM mass ofsolute ×10036040 ×100=11.11%Hence, the concentration of the solution is 11.11%
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