Chlorine can be obtained by the following reaction.
MnO2 + 4HCl MnCl2 + Cl2 + 2H2O
How many grams of HCl react with 25 g of MnO2?
How many grams of Cl2 are formed from this reaction
Answers
Answered by
1
Explanation:
- 140 gram hcl
- sorry i don't know
Answered by
2
Given info : Chlorine can be obtained by the following reaction.
MnO₂ + 4HCl ⇒ MnCl₂ + Cl₂ + 2H₂O
To find :
- How many grams of HCl react with 25g of MnO₂ ?
- How many grams of Cl₂ are formed from this reaction ?
Solution : here we see, 4 mole of HCl react with 1 mole of MnO₂.
molecular mass of MnO₂ = 87 g
Given mass = 25g
so no of moles of MnO₂ = 25/87 = 0.287 mol
so 3.48 mol of MnO₂ react with 4 × 0.287 mol of HCl.
so the required mass of HCl = 4 × 0.287 × molecular mass of HCl
= 4 × 0.287 × 36.5
= 41.9 ≈ 42 g
1 mole of MnO₂ formed 1 mole of Cl₂.
so, 0.287 mole of MnO₂ will produce 0.287 mole of Cl₂
so the mass of Cl₂ = 0.287 × 71 = 20.377 = 20.4 g
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