Question

Chlorine can be prepared by reacting HCl with MnO2. The reaction is represented by the equation: MnO 2(s) + 4HCl  Cl2(g) + MnCl2(aq) + 2H2O(l) Assuming the reaction goes to completion, what mass of HCl solution is needed to produce 142 g of Cl2

Answer 1

The balanced chemical equation for the reaction is:

MnO2(s) + 4HCl(aq) -------> Cl2(g) + MnCl2(aq) + 2H2O(l)

So, 4*(35.5+1)=146 g of HCl reacts with sufficient amount of MnO2 to produce (35.5*2)=71 g of chlorine.

In other words,

71 g of chlorine is obtained from 146 g of HCl .

So, 2.50 g of chlorine is obtained from (146*2.50)/71=5.14 g of HCl

In the conc. HCl solution,

36 g pure HCl is contained in 100 g HCl solution.

So, 5.14 g HCl is contained in (100*5.14)/36=14.3 g HCl solution.

Therefore, 14.3 g of conc. HCl solution is required to produce 2.50 g of chlorine.