Chlorine can be prepared by the reaction: MnO2 1 4 HCl MnCl2 + 2 H2O + Cl2 If 0.394 moles of MnO2 and 61.8 g HCl are available for the reaction, which proceeds until the limiting reaction is consumed, how many grams of Cl2 will be produced?
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Answer:
2+14 = 16
12+2 = 14
so answer is 12
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