Question

Chlorine exists in two isotopic forms .cl-37 and cl-35 but its atomic mass is 35.5

Answer 1

Answer:

1:3

Explanation:

Let relative abundance of Cl-37 be A1% with mass M1=37 amu

∴ The relative abundance of Cl-35 = A2% with mass, M2=35 amu

where A1+A2=100

Thus A2%=(100−A1)%

Using average atomic mass, Mavg=M1A1+M2A2A1+A2

Mavg=37×A1+35×(100−A1)A1+(100−A1)=2A1+3500100

Given that: Mavg=35.5

∴2A1+3500100=35.5

2A1=35.5×100−3500=50

A1=502=25 and A2=100−A1=100−25 =75  

Thus the ratio of isotope abundance of Cl−37toCl−35 is A1:A2=25:75=1:3

Answer 2

Answer:

the ratio of cl 37 and cl 35 is 1:3

Explanation:

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