Question

Chlorine gas is prepared by reaction of H,So, with Mno, and NaCl. What volume of Cl, will be pro
at STP if 50 g of NaCl react with excess amount of Mno, and H,SO?
1) 1.915L
2) 22.4L
3) 11.2 L
4) 9.57 L​

Answer 1

Answer:

11.2 l

Explanation:

please mark me brain liast

Answer 2

Answer:

Chemical reaction involved is:

2NaCl+3H

2

SO

4

+MnO

2

→2NaHSO

4

+MnSO

4

+Cl

2

+2H

2

O

Molar mass of NaCl=23+35.5=58.5 g

According to the balanced reaction 58.5×2=117 g of NaCl produces 1 mol of Cl

2

i.e. 22.4 L at STP.

∴50 g NaCl will produce

117

22.4

×50=9.57 L Cl

2

at STP