Question

Chlorine gas is prepared by reaction of H2SO4 with MnO2 and NaCl.What volume of Cl2 will be produced at STP,if 50g of NaCl react with excess amount of MnO2 and H2SO4

Answer 1

Answer:

Chemical reaction involved is:

2NaCl+3H2SO4+MnO2→2NaHSO4+MnSO4+Cl2+2H2O

Molar mass of NaCl=23+35.5=58.5 g

According to the balanced reaction 58.5×2=117 g of NaCl produces 1 mol of Cl2

​i.e. 22.4 L at STP.

∴50 g NaCl will produce 117/22.4×50=9.57 L Cl2 at STP