Question

Chlorine has two isotopes of 35cl 37cl. the ratio of 35cl and 37cl is 3:1. calculate the relative atomic mass of chlorine​

Answer 1

Answer:

The percent abundance of Cl−35 and Cl−37 is equal to 100.

Let abundance of

35

Cl=x and abundance of

37

Cl=100−x.

As we know,

Atomic weight of

35

Cl= 34.9689

Atomic weight of

37

Cl= 36.9695

Atomic mass of Cl= 35.45

Average atomic mass =

100

34.9689(x)+36.9695(100−x)

=35.45

x=76%

Abundance of Cl−35 = 76%

Abundance of Cl−37 = 24%

Hence, the ratio of their natural abundance is approximately equal to 3:1.

Explanation:

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Answer 2

Answer:

The percent abundance of Cl−35 and Cl−37 is equal to 100.

Let abundance of

35

Cl=x and abundance of

37

Cl=100−x.

As we know,

Atomic weight of

35

Cl= 34.9689

Atomic weight of

37

Cl= 36.9695

Atomic mass of Cl= 35.45

Average atomic mass =

100

34.9689(x)+36.9695(100−x)

=35.45

x=76%

Abundance of Cl−35 = 76%

Abundance of Cl−37 = 24%

Hence, the ratio of their natural abundance is approximately equal to 3:1.