Chlorine has two isotopes of 35Cl and 37Cl. How many different
types of Cl2 molecules can be formed?
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Answer:
The percent abundance of Cl−35 and Cl−37 is equal to 100.
Let abundance of
35
Cl=x and abundance of
37
Cl=100−x.
As we know,
Atomic weight of
35
Cl= 34.9689
Atomic weight of
37
Cl= 36.9695
Atomic mass of Cl= 35.45
Average atomic mass =
100
34.9689(x)+36.9695(100−x)
=35.45
x=76%
Abundance of Cl−35 = 76%
Abundance of Cl−37 = 24%
Hence, the ratio of their natural abundance is approximately equal to 3:1.
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