Question

Chlorine is prepared in the laboratory by treating manganese dioxide (MnO2) with
aqueous hydrochloric acid according to the reaction
4 HCl (aq) + MnO2 (s) → 2H2O (l) + MnCl2 (aq) + Cl2 (g)
How many grams of HCl react with 5.0 g of manganese dioxide?

Answer 1

Answer:

8.39g is the right answer.

Explanation:

Refer attachment for explanation!!!

Answer 2

Answer:

8.4g

Explanation:

5.0g of MnO 2

  contains=  87mol −1 g

5.0g

​

=0.0574 moles

4HCl(aq)+MnO 2   (s)⟶2H2    O+MnCl2    +Cl2    (g)

1 mole of MnO 2

​

reacts with 4 mole of HCl

Thus, 0.0574 mole of MnO 2

​

will react with 4×0.0574 moles of HCl

=0.23 mole of HCl will react with 5g of MnO 2

​

Amount of HCl in 0.23 mole= 0.23×36.5 = 8.4g of HCl

Thus, 8.4g of HCl will react with 5g of MnO 2

​

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