Question

Chlorine is prepared in the laboratory by treating manganese dioxide with aqueous hydrochloric acid according to the reaction:
4HCl (aq) +MnO2 (s) --> MnCl2 (aq) + H2 O (l) +Cl2(g)
How many grams of HCl react with 5.0 g of manganese dioxide?

Answer 1

Answer:

According to the given equation:

MnO2+4HCl→MnCl2+Cl2+2H2O 

1 mole of MnO2 reacts with 4 mole of HCl

or 87 g MnO2 reacts with 146 g HCl

∴ 5 g MnO2 Will react with  87146×5gHCl=8.39HCl