Question

Chlorine is prepared in the laboratory by treating MnO2 with

aqueous hydrochloric acid according to reaction

4 HCl(aq) + MnO2(s) 2H2O(l) + MnCl2(aq) + Cl2(g)

How many grams of HCl react with 5 g of MnO2?

[ Atomic Mass : Cl = 35.5 and Mn =55 u ] Pls answer asap no spam.. ​

Answer 1

Answer:

8.39 grams

Explanation:

1 mole of MnO2 reacts with 4 moles of HCl

so, 87 g of MNO2 reacts with 4*36.5 g of HCl

so, 5 g of MnO2 reacts with 8.39 g of HCl

Answer 2

Answer:

Molecular weight of Mno2 = 87 g

Molecular weight of Hcl = 4 * 36.5 = 146 g

According to chemical reaction

1 g of Mno2 reacts with 4g of Hcl togive = 146/87 * 1

Or

5 g of Mno2 reacts with 4g of Hcl to give = 146/87 *5 = 8.4 g of Hcl

Hence, 8.4 g of HCl will react completely with 5.0 g of manganese dioxide.