Question

Chloroethene, c2h3cl, reacts with oxygen according to the equation below: 2c2h3cl(g) + 5o2(g) 4co2(g) + 2h2o(g) + 2hcl(g) what is the amount, in mol, of h2o produced when 10.0 mol of c2h3cl and 10.0 mol of o2 are mixed together, and the above reaction goes to completion?

Answer 1

Explanation:

Chloroethene, C2H3Cl, reacts with oxygen according to the equation below.

2C2H3Cl(g) + 5O2(g) → 4CO2(g) + 2H2O(g) + 2HCl(g)

What is the amount, in mol, of H2O produced when 10.0 mol of C2H3Cl and 10.0 mol of O2 are mixed together, and the above reaction goes to completion.

It can be answered by ratio and proportion.

First, we need to know the limiting reactant. The reaction demands 2 moles of chloroethene and 5 moles of oxygen. Since we are given equal moles of chloroethene and oxygen as reactants, the limiting reagent would be oxygen since the reaction demands more of oxygen than chloroethene. So we compute the number of moles of water that will be produced based on the limiting reactant, which is oxygen.

According to the equation, 5 moles of oxygen produces 2 moles of water. Doubling the starting # moles of reactant will also double the # moles of product, assuming the reaction is 100% complete. So 5*2 moles of oxygen will produce 2*2 moles of water

Answer 2

4 moles of water will be produced.

Explanation:

$2C_2H_3Cl(g) + 5O_2(g)\rightarrow 4CO_2(g) + 2H_2O(g) + 2HCl(g)$

Moles of Chloroethane = 10.0 moles

Moles of oxygen = 10.0 mol

According to reaction, 5 moles of oxygen reacts with 2 moles of chloroethane .Then 10 moles of oxygen will react with :

$\frac{2}{5}\times 10=4 mol$ of chloroethane

This means that chloroethane is in excess amount and oxygen is in limiting amount.So, the amount of water will depend upon moles of oxygen gas.

According to reaction , 5 moles of oxygen gives 2 molesof water.Then 10 moles of oxygen will give :

$\frac{2}{5}\times 10=4 mol$ of water

Mass of 4 moles of water ;

4 moles of water will be produced.

Learn more about : mole concept and limiting reagent

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