Question

chloropicrin CCL3.NO2 an
insecticide is manufactured by following reaction
CH3NO2 + 3CL2 ----> CCL3.NO2 + 3HCL.
calculate the amount of nitromethane required for preparation of 150 gram ccl3 CCL3.NO2.​

Answer 1

Given:

for the reaction, CH3NO2 + 3CL2 ----> CCL3.NO2 + 3HCL

CCL3.NO2 prepared after reaction = 150g

To Find:

amount of nitromethane required = x =?

Solution:

for the given reaction, Cl2 is the limiting reagent

3mol Cl2 produces 1mol  CCL3.NO2

1mol Cl2 produces 1/3 mol CCL3.NO2

we know that the molar mass of Cl2 = 71 g/mol

the molar mass of CCL3.NO2 = 164 g/mol

the molar mass of CH3NO2 = 61 g/mol

thus, 164/3 g CCL3.NO2 gives 71 g Cl2

           150g CCL3.NO2 gives $\dfrac{71 \times 3 \times 150}{164}$ g Cl2

= 194.81 g Cl2 used

Now,  3mol Cl2 reacts with 1 mol CH3NO2

           194.81 g Cl2 reacts with $\dfrac{194.81 \times 61}{3 \times 71}$

= 55.79 g CH3NO2

thus, 55.79 g  CH3NO2 is required for the preparation

Answer 2

Explanation:

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