Question

chocolate is in the form of a quadrilateral with side 6 cm and 10 cm 5 cm and 5 cm as shown in the figure is cut into two parts on one of its diagonal by a lady part 1 is given to her maid and part 2 is equally divided among a driver and Gardner
the sum of all the angles of a given quadrilateral
the semi perimeter of DBC is
the area of a triangle ABC is ​

Answer 1

Answer: 12 cm2

Step-by-step explanation:

1) The distribution is fair

2) The value depicted here is caring nature, impartialness

Explanation:

There is a figure that goes with this question. The figure is attached.

ΔABD is a right angled triangle

∴ AB² + BD² = AD²

or BD² = AD² - AB²

or BD² = 10² - 6²

or BD² = 100 - 36

or BD² = 64

or BD = 8

Area of ΔABD = 1/2 × 6 × 8 = 24 cm²

Area of ΔBCD can be calculated using Heron's formula

Area =  

semi-parameter s = (5+5+8)/2 = 9

Area =  

       =  

       = 12 cm²

ΔBCD forms Part-I and ΔABD forms Part-II

Part-2 is equally divided between driver and gardener so they both get the chocolate of area 12 cm²

Thus the distribution is fair

The lady has distributed the chocolate among the three indiscriminately. This shows that she cares for all three and there is no biased.