Question

Chocolate is in the form of a quadrilateral with sides 6 cm and 10 cm 5 cm
and 5 cm ( as shown in the figure) iseutin two parts on one of its diagonal
by a lady. part 1 is given to her maid and part 2 is equally divided among a
driver and gardener
A
B
Gom
5cm
TI
lolm
50m
A
(1) length of BD:
9cm
b. 8cm
C.
7cm
d. 6 cm
(II) Area of A ABD :
24 cm
12 cm
b.
C.
42 cm2
21 cm?
d.the sum of all the quadrilateral is equal to
​

Answer 1

Answer:

Answer:

1) The distribution is fair

2) The value depicted here is caring nature, impartialness

Explanation:

There is a figure that goes with this question. The figure is attached.

ΔABD is a right angled triangle

∴ AB² + BD² = AD²

or BD² = AD² - AB²

or BD² = 10² - 6²

or BD² = 100 - 36

or BD² = 64

or BD = 8

Area of ΔABD = 1/2 × 6 × 8 = 24 cm²

Area of ΔBCD can be calculated using Heron's formula

Area = \sqrt{s(s-a)(s-b)(s-c)}

s(s−a)(s−b)(s−c)

semi-parameter s = (5+5+8)/2 = 9

Area = \sqrt{9(9-8)(9-5)(9-5)}

9(9−8)(9−5)(9−5)

= \sqrt{9(4)(4)}

9(4)(4)

= 12 cm²

ΔBCD forms Part-I and ΔABD forms Part-II

Part-2 is equally divided between driver and gardener so they both get the chocolate of area 12 cm²

Thus the distribution is fair

The lady has distributed the chocolate among the three indiscriminately. This shows that she cares for all three and there is no biased.