chocolate is in the form of quadrilateral with sides 6 cm and 10 cm 5 cm and 5 cm is cut into two parts on on of its diagonal by a lady part 1 is given to her maid and part 2 is equally divided among a driver and gardener.1.is it distribution fair.2.what value is depicted
Answers
Answer:
1) The distribution is fair
2) The value depicted here is caring nature, impartialness
Explanation:
There is a figure that goes with this question. The figure is attached.
ΔABD is a right angled triangle
∴ AB² + BD² = AD²
or BD² = AD² - AB²
or BD² = 10² - 6²
or BD² = 100 - 36
or BD² = 64
or BD = 8
Area of ΔABD = 1/2 × 6 × 8 = 24 cm²
Area of ΔBCD can be calculated using Heron's formula
Area =
semi-parameter s = (5+5+8)/2 = 9
Area =
=
= 12 cm²
ΔBCD forms Part-I and ΔABD forms Part-II
Part-2 is equally divided between driver and gardener so they both get the chocolate of area 12 cm²
Thus the distribution is fair
The lady has distributed the chocolate among the three indiscriminately. This shows that she cares for all three and there is no biased.
Explanation:
1) The distribution is fair
2) The value depicted here is caring nature, impartialness
Explanation:
There is a figure that goes with this question. The figure is attached.
ΔABD is a right angled triangle
∴ AB² + BD² = AD²
or BD² = AD² - AB²
or BD² = 10² - 6²
or BD² = 100 - 36
or BD² = 64
or BD = 8
Area of ΔABD = 1/2 × 6 × 8 = 24 cm²
Area of ΔBCD can be calculated using Heron's formula
Area = \sqrt{s(s-a)(s-b)(s-c)}
s(s−a)(s−b)(s−c)
semi-parameter s = (5+5+8)/2 = 9
Area = \sqrt{9(9-8)(9-5)(9-5)}
9(9−8)(9−5)(9−5)
= \sqrt{9(4)(4)}
9(4)(4)
= 12 cm²
ΔBCD forms Part-I and ΔABD forms Part-II
Part-2 is equally divided between driver and gardener so they both get the chocolate of area 12 cm²
Thus the distribution is fair
The lady has distributed the chocolate among the three indiscriminately. This shows that she cares for all three and there is no biased.