Question

choise the right ans.


mathematics. 10th question.



1) the nth term of an arithmetic progression is an=3n+3 then the 3rd term is:

options- a)9. b)12. c)6. d)13.


2)The first term 'p' and common difference 'q; nth term of an arithmetic progression is:

options- a)p+ (n+1)q. b) p-(n+1)q. c) p+(n-1)q. d) p-(n-1)q

​

Answer 1

(1). The nth term of an arithmetic progression is an=3n+3 then the 3rd term is:

• a)9. b)12. c)6. d)13.

$\underline{\sf{\pink{Given}}}$

• $\sf{a_n = 3n+3 }$

$\underline{\sf{\pink{To ~Find}}}$

• $\sf \: 3rd \: \: term$

$\underline{\sf{\pink{Solution}}}$

$\sf{a_n = 3n+3 }$

$\sf{a_3 = 3×3 +3 }$

$\sf{a_3 = 9 +3 }$

$\bf{a_3 = 12}$

• Henceforth, B is the correct option

$\\ \quad \quad \quad \quad \quad \quad \quad \red{ ★}$

2. The first term 'p' and common difference 'q; nth term of an arithmetic progression is:

$\underline{\sf{\pink{Given}}}$

• First term 'p'
• common difference 'q'

$\underline{\sf{\pink{To ~Find}}}$

• nth term of an A.P

$\underline{\sf{\pink{Solution}}}$

$\sf a_n=a+(n-1)d$

• Putting the values

$\bf a_n=p+(n-1)q$

• Henceforth, C is the correct option

Formula :

• $\gray{\boxed{\bf {a_{n}=a_{1}+(n-1)d}}}$

$\sf a_n = the ~nᵗʰ ~term ~in~the1 sequence$

$\sf a_1= the~ first ~term ~in~ the~ sequence$

$\sf d= the ~common ~difference~ between~ terms$

Answer 2

Answer:

1.) Solution :

$a _{n} \: = \: 3n \: + \: 3 \\ a _{3} \: = \: 3 \: \times \: 3 \: + \: 3 \\ a _{3} \: = \: 9 \: + \: 3 \\ a_{3} \: = \: 12.$

• Hence , b is the correct☑️ option.

2.) Solution :

$a _{n} \: = a \: + \: (n \: - 1)d$

• Putting the values

$a _{n} \: = p \: + \: (n \: - 1)q$

• Hence , c is the correct ☑️ option.

★ Don't forget to thanks

★ Mark as brainlist.