Question

Choose a 3-digit number abc is divisible by 11 as 100a+10b+c = *

9(10a+9b) +(a-b+c)

9(10a+b) +(a+b+c)

9(10a+b) +(a-b+c)

11(9a+b) +(a-b+c)​

Answer 1

Answer:

11(9a+b)+(a-b+c) is the right answer